Saturday, April 6, 2019
Titration Lab Essay Example for Free
Titration Lab EssayMethod for conquer of Variables1. In order to take hold the titration of potassium permanganate, we employ the pipette to make the titration constant. We also used the kindred amount of chemical ascendants, with the kindred flaskfuls, to make the titration as constant as possible.2. To control the amount of redox in the experiment, we have used the pipette to keep on putting the same amount of lapse every time. The pipette made the amount of redox constant for every trial, and made the data more(prenominal) accurate. 3. In order to control the amount of potassium permanganate, we have measured the solution with the same case and same scale. Since we have used the same materials, the amount used was very close.4. To control the amount of rend put in to mix the solution, I used my right hand for every trial and did not vary the length and procedure to mix. I have mixed the solution5. In order to control the temperature of the liquids, I have used the same room at the same time. I did not used any air conditioning to change the temperature.Method For Data Collection1. I have weighed push through exactly 2.5 grams of AR ammonium iron (II) sulphate crystals, and dissolved them in approximately 40cm of sulphuric stinging solution with a concentration of approximately 1 mol dm-.2. I did NOT heat the solution to assist the dissolving of the solution.3. I made up to 100cm of the solution into a volumetric flask and mixed the solution.4. I have used the pipette to pipette 10cm of the solution into a conical flask and added close to an equal volume of distilled water.5. I titrated this with 0.0200mol dm- potassium manganate (VII) solution to a faint pink color.6. I reiterate the titration for at least 2 times for accuracy in the data and recorded all the terminations. send back of Raw ResultsTable Showing Volume of KMnO4 Used to React With the SolutionInitial Reading last(a) ReadingVolume of KMnO4The error or uncertainty of this dat a is 0.05cm. However, the uncertainty for the volume difference is not 0.05cm, but is 0.10cm. This is because in that location are two 0.05cm datas, and if you add them up, you will get 0.10cm.EvaluationImprovementsIn this experiment, thither were several inaccurate results and some mistakes I could have improved.1. Pipette For each drop from the pipette, there were same amounts of solutions, but since it is made by human hand, there should have been a little(a) difference in each drop.2. Temperature Although I have done this experiment in one class period, there were slight changes in the weather, causing the temperature to change. This could have affected the data results.3. Force The force applied to the solution and the flask was approximately the same, but there were some differences since it was done by humans. Humans never can do the same exact thing over, and so there should have been a slight error.ConclusionMy speculation for this experiment was correct, because it took about 10 drops to titrate. Although there were some slight errors during the experiment, the experiment itself went fairly come up, as there werent any big outstanding errors in the data and procedures. The main aim of this experiment, titration of redox with potassium permanganate, was well presented, and overall the experiment was good.Problem Calculation1. MnO4- + 8H+ + 5Fe- = Mn2+ + 4H2O + Fe3+2. 5 moles of Fe2+ is required.3. 10cm3 = 0.01dm30.02 mol dm-3 x 0.01 dm3 = 0.0002 mol0.0002 moles of KMnO4 is present.4. MnO4- Fe2+150.0002 mol 0.001 mol0.001 moles of Fe2+ is present in 10cm3 of the solution.5. 0.001 mol x 10 =0.01 mol0.01 moles of Fe2+ is present in 100cm3 of the solution.6. 1 mole of Fe2+ = 56grams56g x 0.01 mol = 0.56g0.56 grams of Fe2+ is in the ammonium iron (II) sulfate7. Number of moles of ammonium iron (II) sulfate = 390.56g/(39mol x 0.1) = 14.4%8. 1 mol of ammonium iron(II) sulfate= (NH4)2Fe(SO4)2 x 6H2O = 2N + 8H+ 1Fe+ 2S + + 12H + 6O = 392 grams56g/392g = 14.3%9. My result was 14.4% and it is almost equal to the correct value which is 14.3%. The difference is only 0.1%.10. The iron (II) salt might unthaw if I heat it, and will affect the result.
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